16x-2x^2=-64

Solution for 16x-2x^2=-64 equation:

16x-2x^2=-64

We move all terms to the left:

16x-2x^2-(-64)=0

We add all the numbers together, and all the variables

-2x^2+16x+64=0

a = -2; b = 16; c = +64;
Δ = b2-4ac
Δ = 162-4·(-2)·64
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16\sqrt{3}}{2*-2}=\frac{-16-16\sqrt{3}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16\sqrt{3}}{2*-2}=\frac{-16+16\sqrt{3}}{-4}
$